Question

John uses an electric iron of 1000 w for 30 minutes a day, a geyser of 2000 N for one hour a day and 7 bulbs of power 100 W for 3 hours a day. The reading of his electricity meter on I June 2016 was 3310. What will be the reading at the end of the month. Also, calculate the amount to be paid if the rate of one unit is RS.4
PLEASE DON'T DO SPAM​

Answer 1

Answer:

Rs. 18.4

Explanation:

answer in the image.

Answer 2

Answer:

E = electrical energy

P = electrical Power

t = time period

Iron-

P = 1000 W

t = 30 mins = ½ hr

t (in 30 days) = ½ hr x 30 = 15 hrs

E = Pxt = 1000 x 15 = 15,000 Wh = 15kwh

Geyser-

P = 2000 W

t = 1 hr

t (in 30 days) = 1 hr x 30 = 30 hrs

E = Pxt = 2000 x 30 = 60,000 Wh = 60kwh

Bulb-

P = 100 W

7 bulbs = 100 x 7 = 700 W

t = 3 hrs

t (in 30 days) = 3hr x 30 = 90 hrs

E = Pxt = 700 x 90 = 63000 Wh = 63kwh

Total Electrical Energy = 63 + 60 + 15 = 138kwh

Cost of 1 kwh = Rs 4

Cost of 138 kwh = Rs 138 x 4 = Rs 552

Hence, Amount to be paid at the end of the month is Rs 552