Question

Joker caps is in the form of right circular cone of base radius 7 cm and height 24cm find the area of the sea required to make 10 such caps.​

Answer 1

GIVEN:-

GIVEN:-radius of cone r = 7cm

GIVEN:-radius of cone r = 7cmheight of cone h = 24cm

GIVEN:-radius of cone r = 7cmheight of cone h = 24cmslant height l = √(24² + 7²) = √(576 + 49) = √625

GIVEN:-radius of cone r = 7cmheight of cone h = 24cmslant height l = √(24² + 7²) = √(576 + 49) = √625l = 25cm

GIVEN:-radius of cone r = 7cmheight of cone h = 24cmslant height l = √(24² + 7²) = √(576 + 49) = √625l = 25cmsince, joker's cap is in the form of right circular cone

GIVEN:-radius of cone r = 7cmheight of cone h = 24cmslant height l = √(24² + 7²) = √(576 + 49) = √625l = 25cmsince, joker's cap is in the form of right circular coneso, area of joker's cap = πrl

GIVEN:-radius of cone r = 7cmheight of cone h = 24cmslant height l = √(24² + 7²) = √(576 + 49) = √625l = 25cmsince, joker's cap is in the form of right circular coneso, area of joker's cap = πrl=> 22/7 × 7 × 25

GIVEN:-radius of cone r = 7cmheight of cone h = 24cmslant height l = √(24² + 7²) = √(576 + 49) = √625l = 25cmsince, joker's cap is in the form of right circular coneso, area of joker's cap = πrl=> 22/7 × 7 × 25=> 22 × 25

GIVEN:-radius of cone r = 7cmheight of cone h = 24cmslant height l = √(24² + 7²) = √(576 + 49) = √625l = 25cmsince, joker's cap is in the form of right circular coneso, area of joker's cap = πrl=> 22/7 × 7 × 25=> 22 × 25=> 550cm²

GIVEN:-radius of cone r = 7cmheight of cone h = 24cmslant height l = √(24² + 7²) = √(576 + 49) = √625l = 25cmsince, joker's cap is in the form of right circular coneso, area of joker's cap = πrl=> 22/7 × 7 × 25=> 22 × 25=> 550cm²so, curved surface area of 1 joker's cap = 550cm²

GIVEN:-radius of cone r = 7cmheight of cone h = 24cmslant height l = √(24² + 7²) = √(576 + 49) = √625l = 25cmsince, joker's cap is in the form of right circular coneso, area of joker's cap = πrl=> 22/7 × 7 × 25=> 22 × 25=> 550cm²so, curved surface area of 1 joker's cap = 550cm²curved surface area 10 joker's cap = 10 × 550 = 5500cm²

GIVEN:-radius of cone r = 7cmheight of cone h = 24cmslant height l = √(24² + 7²) = √(576 + 49) = √625l = 25cmsince, joker's cap is in the form of right circular coneso, area of joker's cap = πrl=> 22/7 × 7 × 25=> 22 × 25=> 550cm²so, curved surface area of 1 joker's cap = 550cm²curved surface area 10 joker's cap = 10 × 550 = 5500cm²I HOPE IT'S HELP YOU DEAR,

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Answer 2

Answer:

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