Math, asked by lenovo99, 10 months ago

Jones covered a distance of 50 miles on his first trip. On a later trip he traveled 300 miles while going three times as fast. His new time compared with the old time was:

(a) three times as much, (b) twice as much, (c) the same, (d) half as much, (e) a third as much

Answers

Answered by ItzLava90
0

Answer:

Let speed of the 1st trip x miles / hr. and speed of the 2nd trip 3x / hr.

We know that

Speed = Distance/Time.

Or, Time = Distance/Speed.

So, times taken to covered a distance of 50 miles on his first trip = 50/x hr.

And times taken to covered a distance of 300 miles on his later trip = 300/3x hr.

= 100/x hr.

So we can clearly see that his new time compared with the old time was: twice as much.

Answer: (b)

Answered by Anonymous
0

Answer:

option ( b) Twice as much

Step-by-step explanation:

On his first trip , Jones covered a distance of 50 miles .

Let his speed be X.

And time taken be 't'.

Now,

Speed = distance / time

X = 50 / t

t = 50/X ...............(1)

Later on he covered 300 miles.

Speed = 3X

Now total time taken,

Time= 300/3X

= 100/X...............(2)

Comparing (1) & (2)

100/X = 50/X

=2

Thus, New time is twice as much as old time.

Similar questions