Chemistry, asked by supriyabhardaj, 1 year ago

jonsi jogs from one and a to the other end B of a straight line 300m road in 2 minutes 50 seconds and then turn around and Fox 100 M back to. See in another one minute what are jerseys average speed and velocity in jogging

Find only A to C.

Answers

Answered by Shreya0909
7
 \textbf{For finding A to C we have to find A to B}

Total distance = 300 m.
Total time = 2 mins 30 s = 150 s.

Average speed =  \dfrac{Total\: distance}{Total\:time}

=  \dfrac{300}{150}


\underline\bold{From\:A\:to\:c}

Total distance = AB + BC .

= 300 m + 100 m.

= 400 m.

TOTAL TIME TAKEN = 2 min 30 s + 1 min.
= 210 s.

FORMULA OF AVERAGE SPEED =  \dfrac{Total\: distance}{Total\:time}

=  \dfrac{400m}{210s}

TOTAL DISPLACEMENT = Length CA

= AB - BC

= 300 m - 100 m

= 200 m

TOTAL TIME = 210s.

AVERAGE VELOCITY =  \dfrac{Displacement}{time}

=  \dfrac{200m}{210s} along CA.

= 0.95 ms

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Answered by arpit2205arpit
5
  1. Total distance = 300 m.
  2. Total time = 2 mins 30 s = 150 s.
  3. Average speed = \dfrac{Total\: distance}{Total\:time}
  4. Totaltime
  5. Totaldistance
  6. = \dfrac{300}{150}
  7. 150
  8. 300
  9. \underline\bold{From\:A\:to\:c}
  10. FromAtoc
  11. Total distance = AB + BC .
  12. = 300 m + 100 m.
  13. = 400 m.
  14. TOTAL TIME TAKEN = 2 min 30 s + 1 min.
  15. = 210 s.
  16. FORMULA OF AVERAGE SPEED = \dfrac{Total\: distance}{Total\:time}
  17. Totaltime
  18. Totaldistance
  19. = \dfrac{400m}{210s}
  20. 210s
  21. 400m
  22. TOTAL DISPLACEMENT = Length CA
  23. = AB - BC
  24. = 300 m - 100 m
  25. = 200 m
  26. TOTAL TIME = 210s.
  27. AVERAGE VELOCITY = \dfrac{Displacement}{time}
  28. time
  29. Displacement
  30. = \dfrac{200m}{210s}
  31. 210s
  32. 200m
  33. along CA.
  34. = 0.95 ms
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