Jose is 3 times as old as wally. 5 years from now, the sum of their ages is 42.how old are they now?
Answers
Answered by
4
let s take,
Jose = x
Jose is 3 times as old as wally
Jose = 3 x x = 3x
wally = x
5 years from now
Jose = 3x - 5
wally = x - 5
Sum of there ages = 42
As per the given problem,
( 3x - 5 ) + ( x - 5 ) = 42
3x - 5 + x - 5 = 42
4x - 10 = 42
4x = 10 + 42
4x = 52
x = 52 / 4
x = 13
Jose s age = 3x - 5 = 3 x 13 - 5 = 34
wally s age = x - 5 = 13 - 5 = 8
I HOPE THIS ANSWER HELPS YOU
Similar questions