Physics, asked by FadedElena001, 6 months ago

What is the change in momentum of a car weighing 1500 kg when its speed increases from 36 km/h to 72 km/h uniformly?​

Answers

Answered by saiyedfazil
21

momentum p1 = mu

= 1500×36=54000

p2 = mv

=1500×72=108000

change in momentum = p2-p1

=108000-54000

= 54000

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Answered by Anonymous
16

Given :-

Mass = 1500 kg

Initial velocity = 36 km/h

Final velocity = 72 km/h

To Find :-

The change in momentum.

Solution :-

We know that,

  • u = Initial velocity
  • m = Mass
  • v = Final velocity

By the formula,

\underline{\boxed{\sf Change \ in \ momentun=mv-mu}}

Given that,

Mass (m) = 1500 kg

Initial velocity (u) = 36 km/h = 10 m/s

Final velocity (v) = 72 km/h = 20 m/s

Substituting their values,

(1500)(20) - (1500)(10)

30000 - 15000

= 15000 kg m/s

Therefore, the change in momentum is 15000 kg m/s.

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