Joseph and Peter can complete a work in 20 hr. and 25 hr. respectively
Find :
(i) work done by both together in 4 hrs.
(ii) work left after both worked together for 4 hrs.
(iii) time taken by Peter to complete the remaining work.
Answers
Step-by-step explanation:
Joseph can complete a work in 20 hrs
Joseph's 1 hour's work = 1/20
Peter can complete a work in 25 hrs
Peter's 1 hour's work = 1/25
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(i) (J + P)'s 1 hour's work = 1/20 + 1/25
= 5+4 / 100
= 9/100
(J + P)'s 4 hour's work = 9/100 × 4
= 9/25 (ans).
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(ii) Whole work = 1
Work done = 9/25
Hence, work left = 1 - 9/25
= 25-9 / 25
= 16/25 (ans).
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(iii) Work left = 16/25
Peter's capacity = 25 hrs
Time taken = 16/25 × 25 = 16 hrs (ans).
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Answer:
Step-by-step explanation: