Question

Joseph goes from A to B at in1hr.The distance between A to B is 54 km.If he needs to cover the same distance within 30 minutes,calculate the factor by which he must increase his speed.

Answer 1

Answer:

Avg speed=1.90 m/s,avg velocity =0.95ms

Step-by-step explanation:

From pont A to B

Distance covered=300m

Displacement=300m

Time taken=2 min 30 sec=(2×60)+30=150 sec

Average speed=TimetakenDistance covered=150300=2 m/sec

Average velocity=TimetakenDisplacement=150300=2 m/sec

From point A to C

Distance covered=300+100=400m

Displacement=300−100=200m

Time taken=3 min 30 sec=(3×60)+30=210 sec

Average speed=TimetakenDistance covered=210400=1.90 m/sec

Average velocity=TimetakenDisplacement=210200=0.95 m/sec