Physics, asked by hilalrather86, 10 months ago

Joseph jogs from 1 end A to the other B of a straight 300 m road in 2 min 50 sec and then turns around and jogs 100m back to C in another 1 min what are Joseph's average speeds and velocities in jogging from A to B and A to C ?

Answers

Answered by samarjain1940
1

Answer:

1.73 m/s

Explanation:

Total Distance = 300 m + 100 m = 400 m

Total Time (in seconds) = 2 min 50 s + 1 min

= 170 s + 60 s

= 230 s

Average Speed = Total Distance / Total Time

= 400 m / 230 s

= 1.73 m/s

I am not sure about the answer.

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