Science, asked by vrahi9380, 10 months ago

Joseph jogs from one end a to the other end b of a straight 300m road in minutes 30 seconds and then turns around and jogs 100m back to point c in another 1 minute.what are joseph's average speeds and velocities in jogging (a) from a to b and (b) from a to c

Answers

Answered by MA200510
2

AFrom pont A to B

Distance covered=300m

Displacement=300m

Time taken=2 min 30 sec=(2×60)+30=150 sec

Average speed=  

Timetaken

Distance covered

​  

=  

150

300

​  

=2 m/sec

Average velocity=  

Timetaken

Displacement

​  

=  

150

300

​  

=2 m/sec

From point A to C

Distance covered=300+100=400m

Displacement=300−100=200m

Time taken=3 min 30 sec=(3×60)+30=210 sec

Average speed=  

Timetaken

Distance covered

​  

=  

210

400

​  

=1.90 m/sec

Average velocity=  

Timetaken

Displacement

​  

=  

210

200

​  

=0.95 m/secnswer

Similar questions