Question

Joseph jogs from one end A to the other end B of a straight 300 m road in 2 minutes 50 seconds and then turns around and jogs 100 m back to point C in another 1 minute. What are Joseph’s average speeds and velocities in jogging (a) from A to B and (b) from A to C?

Answer 1

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$\huge\bold\pink{ANSWER:}$

a) For motion from A to B:-

→Distance covered= 300 m

→Displacement covered= 300m

→Time taken = 2 minutes 30 seconds= 2×60 +30 = 150s

**Average speed= Distance covered/ Time taken = 300m/150s = 2 m/s

**Average velocity= Displacement/Time taken= 300m/150s = 2 m/s

b) For motion from A to B to C:-

→Distance covered= 300+100= 400m

→Displacement covered= AB-CB= 300-100= 200m

→Time taken = 2.50 + 1.00= 3.50 min = 210 s

**Average speed= Distance covered/ Time taken= 400m/210 s = 1.90 m/s

**Average velocity= Displacement/ Time taken = 200m/210 s= 0.952 m/s

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Answer 2

Answer:

Average speed= Distance covered/ Time taken= 400m/210 s = 1.90 m/s

Average velocity= Displacement/ Time taken = 200m/210 s= 0.952 m/s

Explanation: