Question

Joseph​ jogs from one end A to the other end B of a straight 300 m road in 2min 30 sec and then turn around and jigs 100 m back to point C in another 1 minutes​. What are Joseph's average speed and velocities in jogging (a) from A to B and (b) from A to C

Answer 1

Hey Mate! Here's ur answer in the attachment.
I Hope it's correct.
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I Hope It Helps.....☺️
#Yash ^_^

Answer 2

Velocity = dispacement / timeSpeed = distance / time
a) when he jogs from A to B on a straight road,displacement = distance = 300mtime = 2 minutes 30 seconds = 150 s
velocity = 300/150 = 2 m/sspeed = 300/150 = 2m/s
b)when he jogs from A to B and turns back to C,displacement = 300-100 = 200mdistance = 300+100 = 400mtime = 3 minute 30 second = 210 s
velocity = 200/210 = 20/21 m/sspeed = 400/210 = 40/21 m/s
Hope it helps and clear for you