Question

joseph jogs from one end a to the other end b of a straight 300m road in 2 minutes 30 seconds and then turns around and jogs 100m back to point c in another 1 minute what are joseph average speed and velocities in jogging (a) from A to B and (b) fromA to C

Answer 1

Velocity = dispacement / time
Speed = distance / time

a) when he jogs from A to B on a straight road,
displacement = distance = 300m
time = 2 minutes 30 seconds = 150 s

velocity = 300/150 = 2 m/s
speed = 300/150 = 2m/s

b)when he jogs from A to B and turns back to C,
displacement = 300-100 = 200m
distance = 300+100 = 400m
time = 3 minute 30 second = 210 s

velocity = 200/210 = 20/21 m/s
speed = 400/210 = 40/21 m/s

Answer 2

Hi there !☺️

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Solution for your question is in the attached picture.

Let's see some related terms.

⏩ Velocity : Velocity is defined as rate of change of displacement.

It is denoted by 'v'.

⏩ Displacement : Displacement is defined as rate of change of distance.

It is denoted by 's'.

⏩ There are three equation of motion :

1️⃣ v = u + at

2️⃣ s = ut + 1/2 at²

3️⃣ v² - u² = 2as.

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Thanks for the question !

☺️☺️☺️