Question

Joseph jogs from one end to the other end B of a straight 300 road in 2 minutes 30 seconds and then turns around around jobs hundred back 2.3 in another one minute what are the Joseph average speeds and velocities in jogging a from a to b and b from a to C

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Answer 1

Explanation:

(a) A to B

Total distance (s) from A to B = 300m

Time (t) = 2min 30s = (2 x 60) + 30 = 150s

Average speed from A to B= s/t = 300m/150 = 2m/s

Total displacement (s) from A to B = 300m

Time (t) = 2min 30s = (2 x 60) + 30 = 150s

Average velocity From A to B = s/t = 300m/150 = 2m/s

(b) A to C

Total distance (s) from A to C = 300m + 100m = 400m

Time (t) = 2min 30s + 1min = [(2 x 60) + 30] + [60] = 210s

Average speed from A to C = s/t = 400m/210 = 1.90m/s

Total displacement (s) from A to C = 200m

Time (t) = 2min 30s + 1min = [(2 x 60) + 30] + [60] = 210s

Average velocity from A to C = s/t = 200m/210 = 0.95m/s