Question

Joseph trom one and to the other end
300 m road in 2 minutes and the
and jos 100
back to point in another
Joseph's speeds
speed and velocities in jou
B and from A to C
​

Answer 1

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Joseph jogs from one end A to the other end B of a straight 300m road in 2 min 30 sec and then turns around and jogs 100m back to point C in another 1 min what are Joseph average speed and velocities in jogging from A to B and from A to C.

${\bold{\blue{\underline{\red{Exp}\pink{lana}\green{tion}\purple{:-}}}}}$

From A to B,

Given:-

• Total distance (AB) = 300m
• Total time = 2 min 30 sec = 2 × 60 + 30 = 150 sec.

Solution:-

$\bf\:Average\:Speed=\dfrac{Total\:Distance}{Total\:time}$

$\bf\:Average\:Speed=\dfrac{300}{150}$

$\bf\:Average\:speed=2\:m/s$

When Joseph jogs from A to B on a straight road then displacement is equal to distance.

so,

$\bf\:Average\:velocity=\dfrac{Total\:displacement}{Total\:time}$

$\bf\:Average\:velocity=\dfrac{300}{150}$

$\bf\:Average\:velocity=2\:m/s$

From A to C,

Given:-

• Total Distance = AB + BC = 300 + 100 = 400 m
• Total time = 2 min 30 sec + 1 min = 3 min 30 sec = 3 × 60 + 30 = 210 sec

• Displacement = AB - CB = 300 - 100 = 200

Solution:-

$\bf\:Average\:Speed=\dfrac{Total\:Distance}{Total\:time}$

$\bf\:Average\:Speed=\dfrac{400}{210}$

$\bf\:Average\:speed=1.90\:m/s$

then,

$\bf\:Average\:velocity=\dfrac{Total\:displacement}{Total\:time}$

$\bf\:Average\:velocity=\dfrac{200}{210}$

$\bf\:Average\:velocity=0.952\:m/s$