Music, asked by joshd2045, 10 months ago



Joshua wants to burn at least 400 calories per day, but no more than 600. He does this by walking and playing basketball. Assuming he burns 4 calories per minute walking, w, and 5 calories per minute spent playing basketball, b, the situation can be modeled using these inequalities:

4w + 5b ≥ 400

4w + 5b ≤ 600

Which are possible solutions for the number of minutes Joshua can participate in each activity? Check all that apply.
40 minutes walking, 40 minutes basketball
60 minutes walking, 20 minutes basketball
20 minutes walking, 60 minutes basketball
50 minutes walking, 50 minutes basketball
60 minutes walking, 80 minutes basketball
70 minutes walking, 60 minutes basketball
Check all that apply.

Answers

Answered by Badshah123
1

Answer:

hay this is maths question ask this question to in maths section .this is not related to music.

If you want right answer .

right answer is...

20min Walking, 60min basketball.

Answered by tiwariakdi
0

Answer:

The possible solution or the number of minutes Joshua can participate in each activity could be Option D and Option F.

Explanation:

Given the inequalities:

4w+5b\geq 400               .....[1]

4w+5b\leq 600              .....[2]

where w is the walking and b is the basketball

To get the possible solution we will substitute each options given above in inequalities to satisfy the equation;

  • Option A:

w = 40 minutes walking,  b = 40 minutes basketball.

Substitute in [1] we have;

4*40+5*40\geq 400\\160 + 200 \geq  400\\320 \geq 400

Substitute in [2] we have;

4(40)+5(40)\leq 600\\320\leq 600

Option A is not possible because the solution 40 minutes walking, 40 minutes basketball does not satisfy equation [1].

  • Option B:

Similarly, for 60 minutes walking, 20 minutes basketball

Option B is not possible because the solution 60 minutes walking, 20 minutes basketball does not satisfy equation [1].

  • Option C:

for 20 minutes walking, 60 minutes basketball

Option C is not possible because the solution 20 minutes walking, 60 minutes basketball does not satisfy equation [1].

  • Option D:

For 50 minutes walking, 50 minutes basketball.

Substitute in [1] we have;

4*50+5*50\geq 400\\200+250\geq  400\\450\geq  400

Substitute in [2] we have;

4(50)+5(50)\leq 600\\450\leq 600

Option D can be a possible because the solution 50 minutes walking, 50 minutes basketball does satisfy the inequality equation given [1] and [2].

  • Option E:

Similarly, for 60 minutes walking, 80 minutes basketball

Option E is ruled out since the solution of 60 minutes walking and 80 minutes basketball does not satisfy inequality equation [2].

  • Option F:

For 70 minutes walking, 60 minutes basketball.

Substitute in [1] we have;

4*70+5*60\geq 400\\280+300\geq 400\\580\geq 400

Substitute in [2] we have;

4(70)+5(60)\leq 600\\580\leq 600

Option F is  possible because the solution 70 minutes walking, 60 minutes basketball does satisfy the inequality equation [1] and [2].

Therefore, only options D and F are the possible solutions for the number of minutes Joshua can participate in each activity.

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