Question

josna takes 4hrs 30 min in walking a distance and riding back to same place where she started. she could walk both ways in 5 hrs 40 min. the time taken by her to ride back both ways​

Answer 1

Answer:

use simultaneous equations?

Step-by-step explanation:

4 h 30m for a trip to and back (2 trips) 1 riding, 1 walking

5 h 40m divide 2 = 2 hr 50= 1 trip walking

4h 30-2h 50=1 hr 40= 1 bike trip

2 bike trip= 3 h 20

Answer 2

Given :

Time taken by Josna in walking and riding back = 4 hours 30 min

Time taken by her walk both ways = 5 hours 40 min

To find : Time taken by her ride both both ways = ?

Solution :

Let the time taken by walking be 'x'

Let the time taken by riding be 'y'.

So, it becomes :

$x+y=4\ hours\ 30\ min$

and

$2y=5\ hours\ 40\ min\\\\y=2\ hours\ 50\ min$

So, the time taken by walking would be

$4\ hour\ 30\ min-2\ hours\ 50\ min\\\\=1\ hour\ 40\ min$

Hence, the time taken by her to ride both the ways would be

$2\times (1\ hour\ 40\ min)=3\ hours\ 20\ min$