jow fast should aman of mass 50kg run so that his kinetic energy be 625J
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Answered by
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kinetic energy= (1/2)mv^2
according to question
625 = (1/2)(50)v^2
625 = 25v^2
v^2 =625/25 = 25
v^2 = 25
v = 5 m/s should be the velocity of Aman
according to question
625 = (1/2)(50)v^2
625 = 25v^2
v^2 =625/25 = 25
v^2 = 25
v = 5 m/s should be the velocity of Aman
Answered by
0
625= 1/2 mv^2
625=1/2×50×v^2
V^2=25
V=5
625=1/2×50×v^2
V^2=25
V=5
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