Juan's dog stands 2 feet and 3 inches tall. Peter's dog stands 9 inches tall. Use what you have learned about fractions to calculate how much taller Juan's dog is than Peter's dog. Remember that there are 12 inches in one foot.
Answers
Peter's dog = 9 inches
so to find how taller Juan's dog hight is by
27 - 9 = 18 inches or 1 feet and 6 inches .
hope I helped u by my answer
Given:
Height of Juan's dog=2 feet 3 inches
Height of Peter's dog= 9 inches
To find:
The fraction by which Juan's dog is taller than Peter's dog
Solution:
The height of Peter's dog is 2/3rd less than the height of Juan's dog.
We can find the fraction by following the steps given below-
We know that there are 12 inches in one foot.
So, 12 inches=1 foot
We will obtain the heights of both the dogs in inches by using the above information.
The height of Juan's dog=2 feet 3 inches
=(2×12+3) inches
=27 inches
The height of Peter's dog= 9 inches
The difference between the heights of Juan and Peter's do cab be obtained by subtracting the two.
The difference between the height of two dogs=Height of Juan's dog-Height of Peter's dog
=27 inches -9 inches
=18 inches
Now, we will obtain the fraction by which Juan's dog is taller than Peter's dog.
We know that 9 is 1/3rd of 27.
The height of Peter's dog is 1/3rd the height of Juan's dog.
So, the difference between the heights is 2/3rd of the height of Juan's dog.
Therefore, the height of Peter's dog is 2/3rd less than the height of Juan's dog.