Physics, asked by ayushkumar4927, 10 months ago

Judge the equivalent resistance when the following are connected in parallel
a) 1 Ω and 106106 Ω
b) 1 Ω, 103103 Ω and 106106 Ω.​

Answers

Answered by anurag2147
3

Answer:

a)1/1 + 1/106106 = 106106 + 1/106106 = 106107/106106 =

1.000009424Ω

b)1/1 + 1/103103 + 1/106106 = 1 + 0.000009699 +

0.0000094245 = 1.0000191235

Similar questions