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Ten years ago Reena's age was half of
Sona's age.If the ratio of their present
ages is 3:4 ,what will be the sum of
their present ages? *
(3 Points)
Answers
Answered by
176
GivEn:-
- Ten years ago Reena's age was half of Sona's age.
- ratio of their present ages is 3:4
To find:-
- sum of their present ages?
SoluTion:-
✩ Let's assume present age of Reena be 3x years
✩ And present age of Sona be 4x years
✇ Ten years ago Reena's age was half of Sona's age.
⠀⠀
★ So, Their ages before 10 years -
- Age of Reena after 10 years = (3x - 10) years
- Age of Sona after 10 years = (4x - 10) years
⠀⠀ ━━━━━━━━━━━━━━━━━━━━━━━━━━━
✇ According to givEn condition -
Age of Reena = × Age of Sona
★
━━━━━━━━━━━━━━━
✇ Now, Put the value of x in their assumed ages -
- Present age of Reena = 3x = 3 × 5 = 15 years
- Present age of Reena = 4x = 4 × 5 = 20 years
⠀⠀ ━━━━━━━━━━━━━━━━━━━━━━━━━━━
★
━━━━━━━━━━━━━━━
Answered by
102
Given :
- 10 years ago , Reena's age was half of Sona's age .
- The ratio of their present ages is 3:4.
To find :
- Sum of their present ages.
Solution :
Consider,
- Present age of Reena = 3x years
- Present age of Sona = 4x years
According to the question :-
- 10 years ago, Reena's age was half of Sona's age.
10 years ago ,
- Age of Reena = (3x-10) years
- Age of Sona = (4x-10) years
★Present age of Reena = (3×5) = 15 years
★ Present age of Sona = (4×5) = 20 years
The sum of their present ages,
= (15+20) years= 35 years
Therefore, the sum of their present ages is 35 years.
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