Math, asked by ItzTopperGuy, 10 months ago

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Answered by varadhan1971
0

Answer:

0

Step-by-step explanation:

if a+b+c=0

then

a^4+b^4+c^4=

0^4+0^4+0^4=0

then total answer will be zero

Answered by nilesh102
0

hi mate,

solution,

a+b+c = 0

(a+b)² = (-c)²

a²+b²+2ab = c²

(a²+b²-c²)² = (-2ab)²

a⁴+b⁴+c⁴+2a²b²-2b²c²-2c²a² = 4a²b²

a⁴+b⁴+c⁴+2a²b²-4a²b²-2b²c²-2c²a² = 0

a⁴+b⁴+c⁴-2a²b²-2b²c²-2c²a²= 0

a⁴+b⁴+c⁴= 2a²b²+2b²c²+2c²a²

a⁴+b⁴+c⁴= 2(a²b²+b²c²+c²a²)

Substituting this value with

a⁴+b⁴+c⁴/a²b²+b²c²+c²a²

We get,

2(a²b²+b²c²+c²a²)/ a²b²+b²c²+c²a² = 2

i hope it helps you...

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