Justification of 60degree and 90degree
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kavyarajput792000:
Ohh no. I need justification not construction..
sorry
to find 60 degree. 1. draw a ray a b with initial point a. 2. taking a as centre and some radius draw an Arc which intersects ab at point d. 3. taking d as centre and with the same radius as before draw an arc intersecting the previously drawn arc at point e. 4. draw the ray AC passing through e thus, angle c A B is equals 60 degree justification we need to prove angle c a b is equal to 60 degree join d e since arc a d is equal to arc a e using same radius, we drew arc d e
thus their radius will be the same a e equals to a d equals to d e ( radius of equal arc by construction) therefore triangle e a d is an equilateral Triangle angle e a d = 60 degree( all angles of equilateral triangle are 60 degree) angle c a b equals to 60 degree
OKk no prob
2/3 of 90 degree
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Step-by-step explanation:
draw a ray
from one end with the help of compass and pencil draw a semicircle
from the inner end of the semicircle cut an arc measure same as the radius of semicircle on the circumference of the semicircle
from the end of the ray join a line to the arc the angle between the ray and the new line is of 60 degree
same as 90 degree but draw 2 consecutive arc and then bisect them
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