Justify for any pair of resistance the equivalent resistance in parallel
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Given: The resistors.
To find: The correct question is : Justify for any pair of resistance the equivalent resistance in series is greater than equivalent resistance in parallel .
Solution:
- Lets assume there are two resistors each of 6 Ω.
- Let them be in series combination.
- Then the equivalent resistance will be:
6 + 6 = 12 Ω.
- Now let the resistors be in parallel.
- Then the equivalent resistance will be:
1/R = 1/6 + 1/6 = 2/6 = 1/3
R = 3 Ω.
- So from this we can conclude that equivalent resistance in series is greater than equivalent resistance in parallel .
Answer:
So we have concluded that equivalent resistance in series is greater than equivalent resistance in parallel .
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