Chemistry, asked by sumitkumarmurmu9, 9 months ago

justify the statement in rate law . components x and y may or may not be equal to stoichiometric coefficients​

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Answered by Anonymous
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AnswEr :

\underline{\underline{\sf Rate \ Law \colon}}

Rate Law of an equation is an expression that shows the dependence of the rate of reaction on the concentration of the active masses.

Assume a reaction \sf aA + bB \longrightarrow cC + dD

Rate Law would be :

\sf r \propto [A]^a [B]^b

On the basis of steps in a reaction,there are classified into :

  • Elementary Reaction : One step reactions

  • Complex Reactions : Multiple step reactions

If the given reaction is elementary,

  • \sf r = k [A]^a [B]^b

Here,

The variables are equal to the stoichiometric coefficients

If the given reaction is complex,

  • \sf r = k[A]^x[B]^y

Here,

The variables may or may not be equal to the stoichiometric coefficients

Since there are multiple steps in complex reactions,the concentration of the reacting species is variable. As a result,the rate of the reaction is determined by slowest step termed as Rate Determining Step

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