Question

K-1,k+1and2k+3 are in ap find k

Answer 1

$\huge\mathcal{Answer}$

K-1,K+1,2k+3 is in ap.

A1= k-1, A2= K+1 , A3= 2k +3

As we know the series are in ap

So , A2 -A1=A3-A1 .common difference is same

=>(K+1)-(k-1) =(2k+3) -(k+1)

=>k+1 -k+1 = 2k+3-k-1

=>2=k+2

=>2-2 =k

=k = O Answer