Question

(k-1) x^(2) + kx + 1" is " -4 then the value of k is.

Answer 1

Answer:

Step-by-step explanation:

If x+1 is a factor of the polynomial 2x2+kx, then the value of k is. Hence , the value of k is

[x

2

−(k−2)x+k

2

][x

2

+kx+(2k−1)]

For the expression to be a perfect square ,ther are two possible way

(i) When both the quadratic expression are perfect square for a particular value.For this to happen,

k−2=2k→k=−2

Now,for k=−2in the second expression ,we get,

x

2

−2x−5,which is not a perfect square.

(ii)The other way is when both the quadratic equations are same.

−(k−2)=k→k=1+k

2

=2k−1→k=1

At k=1,the expression is a perfect square.

Thus, minimum values of kis 1