Question

(k+1)x²-2(k-1)x+1=0 find tha value of k

Answer 1

Answer:

If the roots of (k+1)x  

2

−2(k−1)x+1=0 are real and equal ; then find the value of k .

Easy

Solution

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Given equation is (k+1)x  

2

−2(k−1)x+1=0

This equation has real and equal roots

⟹Discriminant =0

⟹[−2(k−1)]  

2

−4(k+1)(1)=0

⟹(k−1)  

2

=(k+1)

⟹k  

2

−2k+1=k+1

⟹k  

2

=3k

⟹k=0 or 3

Step-by-step explanation: