Math, asked by Jaisgrewal7104, 1 year ago

(k+1)x2-2(k-1)x+1=0 have equal and real roots find k

Answers

Answered by shivanshibhardwj
8
(-2 (k-1))^2-4 (k+1)(1)=0
4 (k^2+1-2k)-4 (k+1)=0
4k^2+4-8k-4k-4=0
4k^2-4k=0
4k (k-1)=0
k=0/4 or k=0+1
k=0 or k =1
Similar questions