Question

(k+1)x²-2(k-1)x+plus one ​

Answer 1

Solution:

(K+1)x² - 2(K-1)x + 1 = 0

THIS EQUATION HAS EQUAL ROOTS (GIVEN)

THEREFORE, D = 0

A = K + 1

B = -2(K-1)

C = 1

D = 0

B² - 4AC = 0

(2-2K)² - 4(K+1)(1) = 0

4 + 4K² - 8K - 4K - 4 = 0

4K​² - 12K = 0

4K(K-3) = 0

4K = 0   OR   K - 3 = 0

K = 0   OR   K = 3

HOPE, THIS ANSWER HELPS!!!