Question

(K-3)x -(5-k) + (K²- 5K +6)=0 is parallel to y axis​

Answer 1

$\huge\tt\fbox\pink{❥Answer:−}$

$▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬$

Given (k−3)x−(4−k2)y+k2−7k+6=0

a) parallel to x axis

∴y=p p is constant

∴ no x term

so k-3=0

⇒k=3

b) parallel to y axis ∴x=p⇒ no y terms

(k−3)x−(4−k2)y+k2−7k+6=0

⇒−(4−k2)y=0

⇒k2=4       ⇒k=±2

c) passing through origin (0,0)

∴x=0    y = 0

(k−3)x−(4−k2)y+k2−7k+6=0

⇒(k−3)×0−(4−k2)×0+k2−7k+6=0

⇒k2−7k+6=0

⇒k2−6k−k+6=0

⇒k(k−6)−1(k−6)=0

(k−6)(k−1)=0

hence k=6,1

$▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬$

$\huge{\mathtt{\underline{\underline{\color{red}{THANKS}}}}}$

I hope it will help you