Question

(k) 3x + 3(x + 1) + 3(x + 2) = 999​

Answer 1

Answer:

110

Step-by-step explanation:

3x+3(x+1)+3(x+2)= 999

=→ 3x+3x+3+3x+6= 999

=→ 9x= 999-3-6

=→ x= 990/9

=→ x= 110

Hope my answer helps you.

Answer 2

Answer:

x = 110

Step-by-step explanation:

3x + 3(x+1) + 3(x+2) = 999

3x + 3(x+1) + 3(x+2) = 9993x + 3x + 3 + 3x + 6 = 999

3x + 3(x+1) + 3(x+2) = 9993x + 3x + 3 + 3x + 6 = 9999x + 9 = 999

3x + 3(x+1) + 3(x+2) = 9993x + 3x + 3 + 3x + 6 = 9999x + 9 = 9999(x+1) = 999

3x + 3(x+1) + 3(x+2) = 9993x + 3x + 3 + 3x + 6 = 9999x + 9 = 9999(x+1) = 999x + 1 = 999/9

3x + 3(x+1) + 3(x+2) = 9993x + 3x + 3 + 3x + 6 = 9999x + 9 = 9999(x+1) = 999x + 1 = 999/9x + 1 = 111

3x + 3(x+1) + 3(x+2) = 9993x + 3x + 3 + 3x + 6 = 9999x + 9 = 9999(x+1) = 999x + 1 = 999/9x + 1 = 111x = 111 - 1

3x + 3(x+1) + 3(x+2) = 9993x + 3x + 3 + 3x + 6 = 9999x + 9 = 9999(x+1) = 999x + 1 = 999/9x + 1 = 111x = 111 - 1x = 110

Hope it's helpful