Question

(k+4)3 expand formula

Answer 1

$\blue{\huge{\boxed{\star\: Solution \: \star}}}$

===>


$(a + b) {}^{3} = a {}^{3} + b {}^{3} + 3a {}^{2} b + 3ab {}^{2}$


===>
$\red{ \boxed{a = k \: and \: b = 4}}$
===> Put in identity

===>
$k {}^{3} + (4) {}^{3} + 3(k) {}^{2} 4 + 3(k)(4) {}^{2}$

===>
$\green{ \boxed{ \underline{(k + 4) {}^{3} = k {}^{3} + 64 + 12k {}^{2} + 48k}}}$

Answer 2

$\huge\color {green}{\bold{Heya \: friend}}$

${\mathbb{HERE'S YOUR ANSWER}}$

$( {k + 4})^{3} \\ = {k}^{3} + 3 \times {k}^{2} \times 4 + 3 \times k \times 16 + {4}^{3} \\ = {k}^{3} + 12 {k}^{2} + 48k \: + 64$


$\bold{hope \: it \: helps \: u \: }$

$\huge{creamie \: pie}$


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