Question

(k+4)3 To use expansion formulae like this (a+b)3=a3+b3+3ab(a+b) .

Answer 1

k3+43+3k4(k+4)

=k3+64+3×k2×42

=k3+64

Answer 2

Answer:

k^3 +12k^2 + 48k + 64

Step-by-step explanation:

(k+4)^3 = k^3+ 4^3+3×k×4(k+4)

= k^3 + 64 + 12k^2 + 4 8k

=k^3 + 12k^2 +48k +64