Question

k+7sec^2 62degree -7 cot^2 28degree=7sec 0 degree

Answer 1

Answer:

k = 0

Step-by-step explanation:

k+7sec²62° -7 cot²28°=7sec 0°

k+7sec²62° - 7 Cot² (90 - 62)° = 7sec 0°

k + 7 (sec²62° - Tan²62°) = 7 Sec0°  (∵Sec²θ - Tan²θ = 1 and Sec0° = 1)

k + 7 = 7

k = 0.

Answer 2

Answer:

the above answer is correct

Step-by-step explanation:

awesome dude