k.c sinha solution class 10
Attachments:
Mather:
kalu saray...ha?
Answers
Answered by
21
ii) 135 & 225
225=135*1+90
135=90*1+45
90=45*2+0
=>45 is the HCF
iii) 455 & 42
455 =42*10 + 35
42=35*1 + 7
35= 7*5 + 0
=>7 is the HCF
225=135*1+90
135=90*1+45
90=45*2+0
=>45 is the HCF
iii) 455 & 42
455 =42*10 + 35
42=35*1 + 7
35= 7*5 + 0
=>7 is the HCF
Answered by
0
Step-by-step explanation:
chapter number 8.4 ka 13
Similar questions