Question

K(co(c2o4)2(nh3))oxidation no of cobalt

Answer 1

+3
as c2o4 has -2 os.
and nh3 has 0
k has +1
so +
+1-4+0+x=0
×=+3

Answer 2

Cobalt has +3 oxidation number in $K[Co(C_2O_4)_2(NH_3)]$

Explanation:

• The general step to calculate the oxidation number of coordination compound is as follows:

1. Find the overall charge of the given compound.
2. Find the ligands and their charges.
3. The difference between the overall charge and charges of ligand will give the oxidation number of the central metal ion.
4. The overall charge of the compound is equal to its cental metal ion and ligand charges.

• In the case of $K[Co(C_2O_4)_2(NH_3)]$, the central metal ion is Cobalt (Co) and the ligands are $NH_3$ and $C_2O_4$.

Step1: Over all charge:

• When the given form is written in ionic form it gives $[Co(C_2O_4)_2(NH_3)]^{-1}$.
• From this formula, it can be inferred that the over all charge of the compound is -1.

Step 2: Ligands and its charges:

• The compounds contain one neutral ligand and one negative ligand.

• The neutral ligand is $NH_3$ and its charge is 0.
• The negative ligand is $C_2O_4$ and the charge of one molecule is -2. As there are 2 molecules its charge is -4.

Step 3: Charge of central metal ion

• In the given compound, cobalt is the central metal ion.
• Let its charge be x.

∴ The oxidation number of cobalt in  $[Co(C_2O_4)_2(NH_3)]^{-1}$ is calculated using the following equation

x + (-4) + 0 = -1

x - 4 = -1

x = -1+4

x = 3

• Thus the charge of Cobalt in $K[Co(C_2O_4)_2(NH_3)]$ is found as +3.

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