k.e of a moving body decreased by 200% the momentum of the body is decreased by
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Answer:
Momentum of body is decreased by 100%
Explanation:
We know that,
KE = mv² / 2
We also know that,
p = mv
v = p/m
Substituting v = p/m in the equation of KE we get,
KE = mp² / 2m²
KE = p² / 2m
By perentage analysis we get,
ΔKE / KE = 2 Δp / p
Given that,
ΔKE / KE = 200%
Putting this in we get,
2 Δp / p = 200%
Δp / p = 200/2
Δp / p = 100%
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