K.e of body ofass 10 gm and momentum 500gcm\s is equal to
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Answer:
K=(1/2)*mv^2=20j
20= (1/2)*(0.1)v^2
V^2=400
V=20
P=mv= 0.1*20=2
P = 2 g*m/s
hope it helps you,,,,,,,,,,,,,,,,,
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