'K' के किस मान के लिए निम्न समीकरणै दो संपाति रेखाओ को दर्शाएगी। 3x-y+8=0,6x-ky=-16
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Answers
Answered by
12
Answer:
k = 2
Hope it helps....☺✌
Answered by
2
Answer:
3x-y+8=0 let it 1st equ.
6x-ky+16=0 let it 2nd equ.
Step-by-step explanation:
by eleminating x-----------
6(3x-y+8=0)=18x-6y+48
3(6x-ky+16)=18x-3ky+48
by subtracting we get----------
-6y=-3ky let it 3rd equ.
-3ky=-6y
-3ky= -3ky by 3rd equ.
both will be cancelled and answer will be 0(zero).
Hope u understand
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