Question

'K' के किस मान के लिए निम्न समीकरणै दो संपाति रेखाओ को दर्शाएगी। 3x-y+8=0,6x-ky=-16




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Answer 1

Answer:

k = 2

Hope it helps....☺✌

Answer 2

Answer:

3x-y+8=0 let it 1st equ.

6x-ky+16=0 let it 2nd equ.

Step-by-step explanation:

by eleminating x-----------

6(3x-y+8=0)=18x-6y+48

3(6x-ky+16)=18x-3ky+48

by subtracting we get----------

-6y=-3ky let it 3rd equ.

-3ky=-6y

-3ky= -3ky by 3rd equ.

both will be cancelled and answer will be 0(zero).

Hope u understand