Question

k के किस मान के लिए समीकरण युग्म kx+3y=k-3, 12x+ky=k के अपरिमित रूप से अनेक हल होंगे

Answer 1

Answer:

k = 6..... hope it helps you.......

Answer 2

Answer:

when,

k/12=3/k=(k-3)/k then you have infinite solutions

taking,

k/12=3/k

k^2=36

k=±6     ______(1)

now taking,

3/k=(k-3)/k

3=k-3

k=6  _________(2)

by (1) and (2)

k will be 6

your answer is

__k=6__