k. Kanna gets a pocket money of (5a + 3b), (a - 2b) and (3a + 5b) for 3 consecutive weeks.
If her expenditure for the 3 consecutive weeks are (2a + 2b), 2b and (3a + 4b) respectively, then
what is her total savings for 3 weeks?
Answers
Answered by
2
Answer:
Total savings = 4a + 2b
Step-by-step explanation:
Saving for 1st week = (5a+3b) - (2a+2b) = 3a+b
Saving for 2nd week = (a-2b) - 2b = a
Saving for 3rd week = (3a+5b) - (3a+4b) = b
Thus, total savings = 4a + 2b
Answered by
0
Answer:
=3a+b
)
=a - 4b
=1b
Step-by-step explanation:
1st week saving = (5a+3b)-(2a+2b)
=3a+b
2nd week saving=(a - 2b)- (2b)
=a - 4b
3rd week saving=3a+5b - (3a+4b)
=1b
Similar questions