Question

K(s) + 2 H2O (1) 2 KOH (aq) +
H2(g)
(a) How many moles of
water are needed to
react with 3.9 g of
potassium ?​

Answer 1

Answer:

mass of KOH is

(number of moles)×(molar mass) = (0.0997 mol)×(56.1056 g/ mol)

=5.594 g

Explanation:

thus the mass of potassium hydroxide (KOH) produced in the given reaction is 5.594 g

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