K2[Cr(CN)2(O)2(O2)(NH3)] in the given compound oxidation number of Cr is
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O2 shows -1 oxidation state
there fore
os of Cr=-6+2=+4
there fore
os of Cr=-6+2=+4
2017aggaikwad:
give calculation step wise
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Answer : The oxidation number of Cr is (+6).
Explanation :
The given compound is
The oxidation state of given ligands are :
CN (cyno) = -1
O (oxo) = -2
(peroxo) = -2
is a neutral ligand.
Now calculating the oxidation number of negative part of the compound.
Let the oxidation number of Cr (chromium) be 'x'
x = +6
Therefore, the oxidation number of Cr is (+6).
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