K2Cr2O7 + 3H2SO3 + 5H+ ----------->2Cr3+ 3(HSO4)^- + 4H2O
Ratio of equivalents of k2Cr2O7 and H2SO3
Answers
Answer:
Explanation:
his is an oxidation-reduction (redox) reaction:
3 SIV - 6 e- → 3 SVI (oxidation)
2 CrVI + 6 e- → 2 CrIII (reduction)
H2SO3 is a reducing agent, K2Cr2O7 is an oxidizing agent.
Reactants:
H2SO3 – Sulfurous acid
Other names: S(O)(OH)2 Sulphurous acid
K2Cr2O7 – Potassium dichromate
Other names: Potassium dichromateChromium potassium oxide source: , Dipotassium dichromium heptaoxide
Appearance: Red-orange crystalline solid source: wikipedia, accessed: 2019-09-27; Orange-to-red crystals
H2SO4 – Sulfuric acid
Other names: Oil of vitriol , Sulfuric acid, concentrated (> 51% and < 100%) 4, H2SO4
Appearance: Clear, colorless liquid ; Odourless colourless oily hygroscopic liquid ; Colorless to dark-brown, oily, odorless liquid. [Note: Pure compound is a solid below 51°F. Often used in an aqueous solution.]
Products:
KCr(SO4)2 – Chromium potassium sulfate
Other names: Potassium chromium sulfate , Chromium alum, Chrome alum
Appearance: Dark purple needles or greyish-brown powder when anhydrous
H2O – Water, oxidane
Other names: Water (H2O)
Hydrogen hydroxide (HH or HOH)
Hydrogen oxide
Appearance: White crystalline solid, almost colorless liquid with a hint of blue, colorless gas