k2cr2o7 me sirf cr ka oxidation state kyu nikalta hai ?
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Answer:
Explanation:
Oxidation state of K:- +1
Oxidation state of O:- -2
Let the oxidation state of Cr be :- x
And we know that net charge on a compound is 0. Therefore the equation will be :-
1×2+2×x+7×(-2)=0
2+2x-14=0
2x-12=0
2x=12
Therefore, x=12/2=6
So in K2Cr2O7 , the oxidation number of Cr is +6.
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Answer:
Kyunki Cr ke variable oxidation states hote hai; O aur K ke oxidation states GENERALLY badalte nahi hai.
Explanation:
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