Question

K8..find the sum of the series 1 4/5 7/52 10/53 ……….to n terms

Answer 1

sum of n terms= n/2[2a+(n-1)d]. now n=n,a=14/5,d=(-693/260).
now sum of n terms =n/2[2*(14/5)+(n-1)*(-693/260)]