Math, asked by saiprasadstark4252, 11 months ago

कोडे सोडवा हुशारीने 100 रुपयात 100 प्राणी घेऊन दाखवा 1 रुपयाला 1 घोडा 5 रुपयाला 1 हत्ती आणि 1 रुपयाला 4 उंट अट- प्रत्येक प्राणी घ्यावाच लागेल.

Answers

Answered by nidaeamann
1

Answer:

8 camels + 91 horses + 1 elephant = 100 animals

Step-by-step explanation:

As per the given information, the man has total 100 Rupees and he has to buy three animals in such a combination that he uses nearly 100 and he gets a total of 100 animals among three groups.

1 rupee 1 horse

5 rupees 1 elephant

1 rupee 4 camel

The solution to the problem could be sorted as;

Let us say that;

He buys 2 camels, meaning

Number of camels = 8

Price of two camels = 8 / 4 = 2

He buys 91 horses;

Number of horses = 91

Price of 91 horses = 1 x 91 = 91

Then he buys 1 elephant worth 5 rupees

Total items;

8 camels + 91 horses + 1 elephant = 100 animals

Total price

2 + 91 + 5 = 98 near to 100

Answered by Swarup1998
0

Let the number of horses and elephants be x and y. Then there are 100 - (x + y) number of camels.

For a total amount of Rs. 100, we can form an equation:

x + 5y + {100 - (x + y)}/4 = 100

or, 4x + 20y + 100 - x - y = 400

or, 3x + 19y = 300

We have one equation with two unknown variables. That is why we cannot solve it in a direct method. We consider such values of x for which we get integral y.

>>> y = (300 - 3x)/19

We get the following solutions for x, y:

x y

5 15

24 12

43 9

62 6

81 3

Answer:

Horses Elphants Camels

5 15 80

24 12 64

43 9 48

62 6 32

81 3 16

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