Question

कैलकुलेट थे एरिया ऑफ़ थे शेडेड रेगिनीं एच ऑफ़ थे फिगुरेसगिवें बिलो​

Answer 1

Answer:

Shaded Area=Area of rectangle AGJF+ Area of rectangle HCDI+ Area of semi circular ring ABCHG+ Area of semicircular ring DEFJI

Area of rectangle AGJF=25×3.4=85m

2

.

Area of rectangle HCDI=25 3.4=85m

2

.

Area of a ring ABCHG=[(R

2

−r

2

)]=

7

22

[(9.55)

2

−(6.15)

2

]

Area of ring DEFJI=π[(R

2

−r

2

)]=

7

22

[(9.22)

2

−(6.15)

2

]

=(25×3.4)+(25×3.4)+ π[(9.55)

2

−(6.15)

2

]+

2

1

π[(9.55)

2

−(6.15)

2

]

=[85+85+

7

22×15.7×3.4]m

2=(170+167.77)m

2=337.77m 2