*काटकोन त्रिकोणात काटकोन करणाऱ्या बाजू a सेमी व b सेमी यांप्रमाणे आहेत ,तर सर्वांत मोठ्या बाजूची लांबी किती असेल?*
1️⃣ (a+b)² सेमी
2️⃣ √a²+b² सेमी
3️⃣ (a²+b²) सेमी
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Given :- If the sides of a right-angled triangle are equal to a cm and b cm, then what is the length of the largest side ?
1) (a + b) cm
2) √a² + b² cm
3) (a² + b²) cm
Solution :-
we know that,
- In a right angled ∆, pythagoras theorem says that, sum of square of base and perpendicular is equal to square of hypotenuse.
- P² + B² = H² .
- Side opposite to largest angle is longest in length .
- Hypotenuse is opposite to 90° and largest side.
from image we have ,
- ABC is a right angled ∆, right angle at B.
- AB = b cm.
- BC = a cm.
- AC = Hypotenuse .
then,
→ AC² = AB² + BC² (By pythagoras theorem)
→ AC² = (a² + b²)
square - root both sides,
→ AC = √(a² + b²) (2) (Ans.)
Hence, the length of the largest side is √(a² + b²) .
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